Asking again after a person said no

How to do it

A pop-up that returns on every visit until the person gives in is a choice made by fatigue. The Digital Services Act names it in Article 25(3), as Never design a platform interface that deceives or manipulates explains. Keep the decline on the server for signed-in users, so a new device does not ask again. Count "close" and "not now" as a no. Give every prompt one function that decides whether to show it, and test that function.

Examples

JavaScript example

const DAY_MS = 24 * 60 * 60 * 1000
const ASK_AGAIN_AFTER_DAYS = 90

export function mayShowPrompt(lastDeclinedAt, now = new Date()) {
  if (!lastDeclinedAt) return true
  return now.getTime() - lastDeclinedAt.getTime() >= ASK_AGAIN_AFTER_DAYS * DAY_MS
}

Python example

from datetime import datetime, timedelta, timezone

ASK_AGAIN_AFTER = timedelta(days=90)

def may_show_prompt(last_declined_at: datetime | None, now: datetime | None = None) -> bool:
    if last_declined_at is None:
        return True
    now = now or datetime.now(timezone.utc)
    return now - last_declined_at >= ASK_AGAIN_AFTER

How to check

A unit test declines a prompt and asks the function on day 1, day 89 and day 91. It returns false, false and true. A browser test declines a prompt, reloads and visits 10 pages, and the prompt does not appear.

Related rules

• UXD-4 Never design a platform interface that deceives or manipulates in UX and deceptive design